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Text Solution

`r=sqrt(2/15)R``r=2sqrt(1/15)R``r=2/15R``r=2/(sqrt(5))R`

Answer :

BSolution :

`I_(AB)=2/5MR^(2)=I` (given)…….i <br> `I_(A'B)=I_(YY') =I_(YY')+Mr^(2) =I1/2Mr^(2)+Mr^(2)` <br> `=3/2Mr^(2)=1` (given) <br> From eqn i and ii `2/5MR^(2)=3/2Mr^(2)implies r=2/(sqrt(15))R` <br> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/BMS_VOL2_C03_E01_355_S01.png" width="80%">